Integrand size = 22, antiderivative size = 80 \[ \int \frac {d+e x}{\left (d^2-e^2 x^2\right )^{7/2}} \, dx=\frac {d+e x}{5 d e \left (d^2-e^2 x^2\right )^{5/2}}+\frac {4 x}{15 d^3 \left (d^2-e^2 x^2\right )^{3/2}}+\frac {8 x}{15 d^5 \sqrt {d^2-e^2 x^2}} \]
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Time = 0.01 (sec) , antiderivative size = 80, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.136, Rules used = {653, 198, 197} \[ \int \frac {d+e x}{\left (d^2-e^2 x^2\right )^{7/2}} \, dx=\frac {d+e x}{5 d e \left (d^2-e^2 x^2\right )^{5/2}}+\frac {8 x}{15 d^5 \sqrt {d^2-e^2 x^2}}+\frac {4 x}{15 d^3 \left (d^2-e^2 x^2\right )^{3/2}} \]
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Rule 197
Rule 198
Rule 653
Rubi steps \begin{align*} \text {integral}& = \frac {d+e x}{5 d e \left (d^2-e^2 x^2\right )^{5/2}}+\frac {4 \int \frac {1}{\left (d^2-e^2 x^2\right )^{5/2}} \, dx}{5 d} \\ & = \frac {d+e x}{5 d e \left (d^2-e^2 x^2\right )^{5/2}}+\frac {4 x}{15 d^3 \left (d^2-e^2 x^2\right )^{3/2}}+\frac {8 \int \frac {1}{\left (d^2-e^2 x^2\right )^{3/2}} \, dx}{15 d^3} \\ & = \frac {d+e x}{5 d e \left (d^2-e^2 x^2\right )^{5/2}}+\frac {4 x}{15 d^3 \left (d^2-e^2 x^2\right )^{3/2}}+\frac {8 x}{15 d^5 \sqrt {d^2-e^2 x^2}} \\ \end{align*}
Time = 0.42 (sec) , antiderivative size = 82, normalized size of antiderivative = 1.02 \[ \int \frac {d+e x}{\left (d^2-e^2 x^2\right )^{7/2}} \, dx=\frac {\sqrt {d^2-e^2 x^2} \left (3 d^4+12 d^3 e x-12 d^2 e^2 x^2-8 d e^3 x^3+8 e^4 x^4\right )}{15 d^5 e (d-e x)^3 (d+e x)^2} \]
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Time = 2.21 (sec) , antiderivative size = 77, normalized size of antiderivative = 0.96
method | result | size |
gosper | \(\frac {\left (e x +d \right )^{2} \left (-e x +d \right ) \left (8 e^{4} x^{4}-8 d \,e^{3} x^{3}-12 d^{2} e^{2} x^{2}+12 d^{3} e x +3 d^{4}\right )}{15 d^{5} e \left (-x^{2} e^{2}+d^{2}\right )^{\frac {7}{2}}}\) | \(77\) |
trager | \(\frac {\left (8 e^{4} x^{4}-8 d \,e^{3} x^{3}-12 d^{2} e^{2} x^{2}+12 d^{3} e x +3 d^{4}\right ) \sqrt {-x^{2} e^{2}+d^{2}}}{15 d^{5} \left (-e x +d \right )^{3} \left (e x +d \right )^{2} e}\) | \(79\) |
default | \(d \left (\frac {x}{5 d^{2} \left (-x^{2} e^{2}+d^{2}\right )^{\frac {5}{2}}}+\frac {\frac {4 x}{15 d^{2} \left (-x^{2} e^{2}+d^{2}\right )^{\frac {3}{2}}}+\frac {8 x}{15 d^{4} \sqrt {-x^{2} e^{2}+d^{2}}}}{d^{2}}\right )+\frac {1}{5 e \left (-x^{2} e^{2}+d^{2}\right )^{\frac {5}{2}}}\) | \(90\) |
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Leaf count of result is larger than twice the leaf count of optimal. 171 vs. \(2 (68) = 136\).
Time = 0.30 (sec) , antiderivative size = 171, normalized size of antiderivative = 2.14 \[ \int \frac {d+e x}{\left (d^2-e^2 x^2\right )^{7/2}} \, dx=\frac {3 \, e^{5} x^{5} - 3 \, d e^{4} x^{4} - 6 \, d^{2} e^{3} x^{3} + 6 \, d^{3} e^{2} x^{2} + 3 \, d^{4} e x - 3 \, d^{5} - {\left (8 \, e^{4} x^{4} - 8 \, d e^{3} x^{3} - 12 \, d^{2} e^{2} x^{2} + 12 \, d^{3} e x + 3 \, d^{4}\right )} \sqrt {-e^{2} x^{2} + d^{2}}}{15 \, {\left (d^{5} e^{6} x^{5} - d^{6} e^{5} x^{4} - 2 \, d^{7} e^{4} x^{3} + 2 \, d^{8} e^{3} x^{2} + d^{9} e^{2} x - d^{10} e\right )}} \]
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Result contains complex when optimal does not.
Time = 7.23 (sec) , antiderivative size = 604, normalized size of antiderivative = 7.55 \[ \int \frac {d+e x}{\left (d^2-e^2 x^2\right )^{7/2}} \, dx=d \left (\begin {cases} - \frac {15 i d^{4} x}{15 d^{11} \sqrt {-1 + \frac {e^{2} x^{2}}{d^{2}}} - 30 d^{9} e^{2} x^{2} \sqrt {-1 + \frac {e^{2} x^{2}}{d^{2}}} + 15 d^{7} e^{4} x^{4} \sqrt {-1 + \frac {e^{2} x^{2}}{d^{2}}}} + \frac {20 i d^{2} e^{2} x^{3}}{15 d^{11} \sqrt {-1 + \frac {e^{2} x^{2}}{d^{2}}} - 30 d^{9} e^{2} x^{2} \sqrt {-1 + \frac {e^{2} x^{2}}{d^{2}}} + 15 d^{7} e^{4} x^{4} \sqrt {-1 + \frac {e^{2} x^{2}}{d^{2}}}} - \frac {8 i e^{4} x^{5}}{15 d^{11} \sqrt {-1 + \frac {e^{2} x^{2}}{d^{2}}} - 30 d^{9} e^{2} x^{2} \sqrt {-1 + \frac {e^{2} x^{2}}{d^{2}}} + 15 d^{7} e^{4} x^{4} \sqrt {-1 + \frac {e^{2} x^{2}}{d^{2}}}} & \text {for}\: \left |{\frac {e^{2} x^{2}}{d^{2}}}\right | > 1 \\\frac {15 d^{4} x}{15 d^{11} \sqrt {1 - \frac {e^{2} x^{2}}{d^{2}}} - 30 d^{9} e^{2} x^{2} \sqrt {1 - \frac {e^{2} x^{2}}{d^{2}}} + 15 d^{7} e^{4} x^{4} \sqrt {1 - \frac {e^{2} x^{2}}{d^{2}}}} - \frac {20 d^{2} e^{2} x^{3}}{15 d^{11} \sqrt {1 - \frac {e^{2} x^{2}}{d^{2}}} - 30 d^{9} e^{2} x^{2} \sqrt {1 - \frac {e^{2} x^{2}}{d^{2}}} + 15 d^{7} e^{4} x^{4} \sqrt {1 - \frac {e^{2} x^{2}}{d^{2}}}} + \frac {8 e^{4} x^{5}}{15 d^{11} \sqrt {1 - \frac {e^{2} x^{2}}{d^{2}}} - 30 d^{9} e^{2} x^{2} \sqrt {1 - \frac {e^{2} x^{2}}{d^{2}}} + 15 d^{7} e^{4} x^{4} \sqrt {1 - \frac {e^{2} x^{2}}{d^{2}}}} & \text {otherwise} \end {cases}\right ) + e \left (\begin {cases} \frac {1}{5 d^{4} e^{2} \sqrt {d^{2} - e^{2} x^{2}} - 10 d^{2} e^{4} x^{2} \sqrt {d^{2} - e^{2} x^{2}} + 5 e^{6} x^{4} \sqrt {d^{2} - e^{2} x^{2}}} & \text {for}\: e \neq 0 \\\frac {x^{2}}{2 \left (d^{2}\right )^{\frac {7}{2}}} & \text {otherwise} \end {cases}\right ) \]
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Time = 0.20 (sec) , antiderivative size = 80, normalized size of antiderivative = 1.00 \[ \int \frac {d+e x}{\left (d^2-e^2 x^2\right )^{7/2}} \, dx=\frac {x}{5 \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}} d} + \frac {1}{5 \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}} e} + \frac {4 \, x}{15 \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {3}{2}} d^{3}} + \frac {8 \, x}{15 \, \sqrt {-e^{2} x^{2} + d^{2}} d^{5}} \]
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\[ \int \frac {d+e x}{\left (d^2-e^2 x^2\right )^{7/2}} \, dx=\int { \frac {e x + d}{{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {7}{2}}} \,d x } \]
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Time = 9.87 (sec) , antiderivative size = 78, normalized size of antiderivative = 0.98 \[ \int \frac {d+e x}{\left (d^2-e^2 x^2\right )^{7/2}} \, dx=\frac {\sqrt {d^2-e^2\,x^2}\,\left (3\,d^4+12\,d^3\,e\,x-12\,d^2\,e^2\,x^2-8\,d\,e^3\,x^3+8\,e^4\,x^4\right )}{15\,d^5\,e\,{\left (d+e\,x\right )}^2\,{\left (d-e\,x\right )}^3} \]
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